+alex008 Posted November 22, 2012 Report Share Posted November 22, 2012 Au inceput sa apara unii profi cu modele de bac 2013. De unde le iau ca nu resuesc sa gasesc decat la mate si as avea nevoie pt fizica. Daca intereseaza pe cineva la mate le poate lua de aici Quote Link to comment Share on other sites More sharing options...
Moderators Courage Posted November 22, 2012 Moderators Report Share Posted November 22, 2012 Dacă vrei, am eu 100 de modele din 2009 ... (la fizică), optică. Cred că găsesc şi electricitate ... L.E. Da, am şi la electricitate Quote Link to comment Share on other sites More sharing options...
+Lus Posted November 22, 2012 Report Share Posted November 22, 2012 Toti avem... la toate. Anyway, am facut varianta in mare, din priviri, si a iesit un 6, si nu m-am chinuit. Incurajator. Quote Link to comment Share on other sites More sharing options...
Moderators Solution Courage Posted November 22, 2012 Moderators Solution Report Share Posted November 22, 2012 Uite modelele de la minister pentru BAC 2013 la toate materiile! http://subiecte2013.edu.ro/2013/bacalaureat/modeledesubiecte/probescrise/ 1 Quote Link to comment Share on other sites More sharing options...
+alex008 Posted November 22, 2012 Author Report Share Posted November 22, 2012 merci fain Cele din 2009 le am si eu si la mate m2 si la fizica mecanica si parca si curent continuu. Quote Link to comment Share on other sites More sharing options...
+alex008 Posted December 28, 2012 Author Report Share Posted December 28, 2012 Daca are cineva raspunsurile (corecte) la grila (partea I) pt fizica subiecte 2009 pt electricitate il rog sa mi le dea si mie. Quote Link to comment Share on other sites More sharing options...
+alex008 Posted January 6, 2013 Author Report Share Posted January 6, 2013 Si acum sa vedem care-i tare la fizica punctele c si d de la probema data Quote Link to comment Share on other sites More sharing options...
+GodsOtherHand Posted January 6, 2013 Report Share Posted January 6, 2013 val minima nu e gen... i= u/r unde u=40v si r = 1 (aia interna) + 4 (alea 2 in paralel) + 6 (rezistenta maxima a firului). deci i = 40 / 11 (sau minima se refera valoarea intensitatii ce trece prin R2? eu am facut care trece prin sursa..) revin si cu Cul imediat suma caderilor de tensiune pe circuit tre sa fie 0, nu? deci pe rezistenta echivalenta de 5 ohmi (aia interna + aia paralele) vom avea 25v. (40 - 15) => i= 5A. => Rnecunoscut = 3 ohmi. Foarte probabil sa fi gresit, am avut probleme mari la capitolu asta, si am cam uitat de la ultimu examen.. 1 Quote love is a verb Love is a doing word Link to comment Share on other sites More sharing options...
+alex008 Posted January 6, 2013 Author Report Share Posted January 6, 2013 d-ul asa se pare ca este.. c-ul acuma ma uit pe el. Apropo fara suparare nu vreau sa fiu critic, dar sa stii ca nu poti nota la examen tensiunea oricum (E, U sau e) pt ca E=U+u Quote Link to comment Share on other sites More sharing options...
+GodsOtherHand Posted January 6, 2013 Report Share Posted January 6, 2013 habar nam cine e E, u sau U. imi explici te rog? Quote love is a verb Love is a doing word Link to comment Share on other sites More sharing options...
+alex008 Posted January 6, 2013 Author Report Share Posted January 6, 2013 ete na... cum sa nu sti E- tensine electromotoare U- caderea de tensiune la borne/pe o portiune si u tensiunea interna a sursei Quote Link to comment Share on other sites More sharing options...
+GodsOtherHand Posted January 6, 2013 Report Share Posted January 6, 2013 noi le notam pe toata cu U pentru ca la urma urmei sunt acelasi lucru... daor ca aia interna deobicei o scoatem afara si consideram sursa ideala, si aia dlectromotoare (alimentarea) e o tensiune ca oricare alta again (fata de masa) 1 Quote love is a verb Love is a doing word Link to comment Share on other sites More sharing options...
+alex008 Posted January 6, 2013 Author Report Share Posted January 6, 2013 Ms fain pt ajutor! Am ajuns la mal cu problema Quote Link to comment Share on other sites More sharing options...
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