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Descarcare Modele Subiecte Bac 2013


alex008
Go to solution Solved by Courage,

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val minima nu e gen...

 

i= u/r unde u=40v si r = 1 (aia interna) + 4 (alea 2 in paralel) + 6 (rezistenta maxima a firului).

 

deci i = 40 / 11

(sau minima se refera valoarea intensitatii ce trece prin R2? eu am facut care trece prin sursa..)

 

revin si cu Cul imediat :D

 

 

suma caderilor de tensiune pe circuit tre sa fie 0, nu? deci pe rezistenta echivalenta de 5 ohmi (aia interna + aia paralele) vom avea 25v. (40 - 15) => i= 5A. => Rnecunoscut = 3 ohmi.

 

 

Foarte probabil sa fi gresit, am avut probleme mari la capitolu asta, si am cam uitat de la ultimu examen.. :D

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