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Explicatii Rezolvare Limite De Functii

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Pentru tipul de ecuatii cum ai zis tu, vezi asta: http://www.pro-didactica.ro/forum/index.php?forumID=8&ID=24230

Se pomeneste acolo despre impartirea polinoamelor. Ai aici: http://mate123.ro/formule-matematice-algebra-liceu-generala/impartirea-polinoamelor/




La a:




La d:







deci limita devine:





Iar la e:




Posibil să fi greşit la calcul. N-am stat să verific :)

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x3 + 5x2 + 7x + 2 = (x + 2)(x2 + 3x + 1)

x2 + x - 2 = (x - 1)(x + 2)


2x3 - 5x2 - 2x - 3 = (x - 3)(2x2 + x + 1)

x3 - x2 - 7x + 3 = (x - 3)(x2 + 2x + 1)



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