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Explicatii Rezolvare Limite De Functii


Graham777
Go to solution Solved by Courage,

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Pentru tipul de ecuatii cum ai zis tu, vezi asta: http://www.pro-didactica.ro/forum/index.php?forumID=8&ID=24230

Se pomeneste acolo despre impartirea polinoamelor. Ai aici: http://mate123.ro/formule-matematice-algebra-liceu-generala/impartirea-polinoamelor/

 

 

 

La a:

u586hTR.gif

 

 

La d:

 

IPfMxst.gif

 

 

pRnncSQ.gif

 

deci limita devine:

 

2C8SdR1.gif

 

 

Iar la e:

 

FHY2n1S.gif

 

Posibil să fi greşit la calcul. N-am stat să verific :)

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x3 + 5x2 + 7x + 2 = (x + 2)(x2 + 3x + 1)

x2 + x - 2 = (x - 1)(x + 2)

 

2x3 - 5x2 - 2x - 3 = (x - 3)(2x2 + x + 1)

x3 - x2 - 7x + 3 = (x - 3)(x2 + 2x + 1)

 

http://www.wolframalpha.com/widget/widgetPopup.jsp?p=v&id=7014d9722bc42de3f621eaad1da2615e&title=Simplifying%20Algebraic%20Expressions%20Calculator&theme=blue&i0=9x-9y^3&podSelect=

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